(3x-60)+(x+20)+(1/2x+40)^2=180

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Solution for (3x-60)+(x+20)+(1/2x+40)^2=180 equation: 



(3x-60)+(x+20)+(1/2x+40)^2=180

We move all terms to the left:

(3x-60)+(x+20)+(1/2x+40)^2-(180)=0



Domain of the equation: 2x+40)^2!=0

x∈R



We get rid of parentheses

3x+x+(1/2x+40)^2-60+20-180=0

We multiply all the terms by the denominator


3x*2x+40)^2+x*2x+40)^2+(1-60*2x+40)^2+20*2x+40)^2-180*2x+40)^2=0

We add all the numbers together, and all the variables

3x*2x+40)^2+x*2x+40)^2+(-60*2x+41)^2+20*2x+40)^2-180*2x+40)^2=0

Wy multiply elements

6x^2+40)^2+x*2x+40)^2+(-60*2x+41)^2+20*2x+40)^2-180*2x+40)^2=0

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